´ò¿ª¹ÈÆÙAPPä¯ÀÀ
Íƹã²É¹ºÉϹÈÆÙ»·±£
Á¢¼´´ò¿ª
  • ²úÆ·
  • ÏêÇé
ȼÆø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß
£¤28000.00
¹ã¶«ÖÐɽ
ÖÐɽÊÐÊÀͨÊäËÍ»úеÉ豸ÓÐÏÞ¹«Ë¾
5Äê | Ö¸Êý£º110 | ¹¤ÉÌÒÑÈÏÖ¤
µêÆÌÍƼö
  • ͼÎÄÏêÇé
  • ²úÆ·²ÎÊý
ȼÆø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß  ÖÐɽÊÐÊÀͨÊäËÍ»úеÉ豸ÓÐÏÞ¹«Ë¾Éú²ú
Èý£º¼¼Êõ±ê×¼
1. ¶¯Á¦
(1). ÆøÔ´:
    Ñ¹Á¦:4-6Bar;
    ÈÝÁ¿£ºÔ¼4m3  Âò·½¸ºÔ𽫷½¹ÜÒýµ½ÏßÌ帽½ü¡£
    ÒªÇó£ºÏßÌåÈë¿Ú´¦Éè×ÜÆø·§¼°Â˳¾¡¢ÓÍË®¹ýÂË¡¢µÈ¹¦ÄÜÆ÷¼þ¡£
£¨2£©µçÔ´£º
    ¹æ¸ñ£º50HZÈýÏà380V£¬Âò·½¸ºÔ𽫰´µ½ÏßÌåµ£µç¿ØÏäÄÚ¡£
2.ÏßÌå×°±¸ÅäÖÃ˵Ã÷  ȼÆø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß

(1).ÏßÌå:µ¥²ã±¶ËÙÁ´,Ö÷ÏßÌå×ܳ¤25Ã×(º¬¹ý¶É¶ÎºÍÏßÌ嶯Á¦²¿·Ý£©£¬±¾ÏßÉ豸Óж¥Éý4̨
   Æ½Òƹý¶É2̨£¬×èµ²Æø¸×16¸ö¡£È¼Æø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß
(2).ÑÕÉ«£ºÏßÌåËùÓÐÌú¼þÐè¾­Ë«·Å¼ÆÂÛºóÈ·¶¨£¬²ÉÓÃ*ÅçËÜ´¦Àí¡£
£¨3£©.Ö§¼Ü:  ÏßÌå½ÅÖ§¼Ü²ÉÓÃ40*40·½¹Ü,ºñ¶È2.0MM,(¶¯Á¦¼Ü²ÉÓÃ40*40*2.5MM·½¹Ü£©
£¨3£©.ÕÕÃ÷:ÏßÌåÉϹ¤Î»½ô²¼T5µ¥Ö§´øÕÖ½ÚÄܵơ£È¼Æø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß
(4).×÷ÒµÖ¸µ¼Êé:È«ÏßÌåÿ¹¤Î»ÅäÓÐ×÷ÒµÖ¸µ¼Êé¼Ü,ÿ¹¤Î»ÅäÒ»Ì×A4°åÓлú²£Á§°å
(5).×èµ²Æ÷:È«ÏßÅä×èµ²Æ÷¹²16¸ö,Åä16¸ö½Å̤·§ÓÉÔ±¹¤½Å²Èʽ¿ØÖÆ.
ȼÆø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²úÏß
Æ·ÅÆ£ºÊÀͨ
¼Ó¹¤¶¨ÖÆ£ºÊÇ
ÐͺţºG4646
ÓÃ;£ºÈ¼Æø±Ú¹Ò¯Éú²úÏß ±Ú¹Ò¯×é×°Éú²
ÄÚÈÝÉùÃ÷£º¹ÈÆÙ»·±£ÎªµÚÈý·½Æ½Ì¨¼°»¥ÁªÍøÐÅÏ¢·þÎñÌṩÕߣ¬¹ÈÆÙ»·±££¨º¬ÍøÕ¾¡¢¿Í»§¶ËµÈ£©ËùչʾµÄÉÌÆ·/·þÎñµÄ±êÌâ¡¢¼Û¸ñ¡¢ÏêÇéµÈÐÅÏ¢ÄÚÈÝϵÓɵêÆ̾­ÓªÕß·¢²¼£¬ÆäÕæʵÐÔ¡¢×¼È·ÐԺͺϷ¨ÐÔ¾ùÓɵêÆ̾­ÓªÕ߸ºÔð¡£¹ÈÆÙ»·±£ÌáÐÑÄú¹ºÂòÉÌÆ·/·þÎñÇ°×¢Òâ½÷É÷ºËʵ£¬ÈçÄú¶ÔÉÌÆ·/·þÎñµÄ±êÌâ¡¢¼Û¸ñ¡¢ÏêÇéµÈÈκÎÐÅÏ¢ÓÐÈκÎÒÉÎʵģ¬ÇëÔÚ¹ºÂòǰͨ¹ý¹ÈÆÙ»·±£ÓëµêÆ̾­ÓªÕß¹µÍ¨È·ÈÏ£»¹ÈÆÙ»·±£É豸ÍøÉÏ´æÔÚº£Á¿µêÆÌ£¬ÈçÄú·¢ÏÖµêÆÌÄÚÓÐÈκÎÎ¥·¨/ÇÖȨÐÅÏ¢£¬ÇëÔÚ¹ÈÆÙ»·±£PC°æÊ×Ò³µ×À¸Í¶ËßͨµÀ½øÐÐͶËß¡£